9w^2+11w+10=-10w

Solution for 9w^2+11w+10=-10w equation:

9w^2+11w+10=-10w

We move all terms to the left:

9w^2+11w+10-(-10w)=0

We get rid of parentheses

9w^2+11w+10w+10=0

We add all the numbers together, and all the variables

9w^2+21w+10=0

a = 9; b = 21; c = +10;
Δ = b2-4ac
Δ = 212-4·9·10
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-9}{2*9}=\frac{-30}{18}
=-1+2/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+9}{2*9}=\frac{-12}{18}
=-2/3
$